 Hello and welcome to the session. In this session we will discuss one area theorem. According to this theorem we have the area is equal to a triangle on the same base in altitude. To prove this theorem, consider this figure in which we are given and the rectangle has the same altitude qt. The theorem we have that the area of the parallelogram is equal to the area of the rectangle on the same base and of same altitude. So, as both the parallelogram pqrs and rectangle pqs pq and also they have the same altitude qt, we are supposed to prove is equal to the area. Let us now start with the proof rectangle. So, all the angles at this rectangle would be of measure 90 degrees and so t is of measure 90 degrees and also angle qtx is of measure 90 degrees. And we also know that qt is the altitude of both the parallelogram and the rectangle. Now, consider the right triangle rpq. In these two right triangles is equal to qt. The opposite side triangle opposite sides are equal so px is equal to qt. Then the hypotenuse ps of triangle is equal to the hypotenuse of the right triangle rpq which is qr. So, the opposite sides know that opposite sides of the parallelogram are equal. Also is equal to angle qtr as each is equal to 90 degrees. Therefore, using this result, we can say that the triangle pq by the rh is Iteria. The congruence is equal to the area of the triangle rtq figure qts of triangle lateral qts is equal to area of triangle rtq plus the quadrilateral pqts. And now, when I am adding the quadrilateral pqxs, we get the quadrilateral pqts to the triangle rpq. We get to be equal to area of the parallelogram. This is what we were supposed to give altitude are equal. In this session, hope you understood the area theorem discussed.