 I welcome to our session where we discuss the following question. It says two unhyped power forces, p and q, where p is greater than q, act as two points, x units, apart. So rather than the direction of force p be reversed, the resultant will be displayed by a distance 2 p q by p squared minus q squared into x units. And with the solution, we have two cases. In case one, we have when p and q are unhyped power forces. Force p acts at point A, and force q acts at point B. Now, as in the question, we are given that force p is greater than q, so that resultant of these two forces will act at point, say, c. And resultant will be equal to p minus q. Then q is equal to p minus q. These are at a distance of x units from each other. Force p is reversed. Force p is parallel to force q. Then we have to show that the distance 2 p q by p squared minus q squared into x q is equal to A v by p plus q. Let's say this equation is 1, and this as 2. Consider dc. Now, dc is equal to 2. We know that 2 q 1 by p minus q. p minus q into p plus q, q squared into A, a distance 2 p2 by p squared minus q squared into x units. So this completes the session. Bye, and take care.