 Hi and welcome to the session. Let's work out the following question. The question says a chord AB of a circle of radius 14 cm makes the right angle at the center O of the circle pying the area of the minor segment. That means we have to find the area of this shaded region where AB is the chord of the circle. Take pi to be equal to 22 by 7. Let's start with the solution to this question. We see that area of minor segment will be equal to area of the sector minus area of triangle A O B. This is equal to theta by 360 degree pi r square minus r square by 2 sin theta. Because we know that area of the sector is theta that is 90 degree in this case divided by 360 into pi r square minus area of the triangle A O B will be half of product of two of its sides into sin of angle included between them that is 90 degree. So now this is equal to 90 by 360 or 90 degree by 360 into 22 by 7 radius is 14 so into 14 square minus 14 square by 2 into sin 90 degree. This is equal to 1 by 4 into 22 into 14 into 2 minus 14 into 7 into 1 because sin 90 degrees 1 this is equal to 154 minus 98 which is further equal to 56 centimeter square. So our answer to this question is that the area of the minor segment that is this match area is 56 centimeter square. So I hope that you understood the solution and enjoyed the session. Have a good day.