 Hi and welcome to our session. Let us discuss the following question. The question says a hemisphere of length of radius 8 cm is cast into a right circular cone of base radius 6 cm. Determine the height of the cone, correct to 2 places of decimal. And this is the hemisphere of whose radius is 8 cm. This is cast into a right circular cone of base radius 6 cm. We have to find the height of the cone. Let's now begin with the solution. Now let h be the height of right circular cone. We are given that base radius of right circular cone is 6 cm. So volume of right circular cone 1 by 3 by r square that is 6 square into h. We are also given that radius of hemisphere 8 cm. So volume of hemisphere is 2 by 3 by 8 cm. Now since hemisphere is casted into a right circular cone, therefore volume of right circular cone is equal to volume of hemisphere. The volume of right circular cone is 1 by 3 by 6 square h and volume of hemisphere is 2 by 3 by 8 cm. Now cancel pi from both sides. So this implies h is equal to 2 into 8 into 8 into 8 into 3 divided by 6 into 6 into 3. Cancel 3 from both numerator and denominator. 2 divided by 6 gives us 1 by 3. Canceling 8 by 6 we get 4 by 3. So now we have 256 divided by 9. And this is equal to 28.5 cm. Hence our required answer is 28.5 cm. So this completes the session. Bye and take care.