 A polynomial p of m is given as 2 times m to the power 90 plus of 9m minus 1 is 0, a 0 of p of m. So first of all let us try to get some clarity on this statement. Is the number 0, we are talking about the number 0, a 0 of p of m. What do we mean by this 0? This 0 means we are thinking about, we are talking about that particular value of m or maybe more than one values of m that would make this polynomial p of m equal to 0. So what we need to find here is that, is this number 0, can this number 0 act as the 0 of this p of m? This number 0 can only act as 0 of p of m, if on substituting m as 0 in this given polynomial, the value of this polynomial would turn out to be 0. Let us try and see that. So 2 times instead of m let us substitute 0, 2 times 0 to the power 90 plus of 9 times m instead of m we are substituting 0 minus of 1, minus of 1. Let us actually see whether this value is equal to 0 or not. So this would give us 0 to the power 90 is 0, 9 times 0 is 0 and minus 1, 2 times 0 would give us 2, sorry not 2, 0, 2 times 0 is 0 plus 9 times 0 is again 0 minus 1. So this value is negative 1 which is not equal to 0. On substituting 0 instead of m in this polynomial, the value of this polynomial is negative 1 which is not equal to 0. Hence this number 0 is not the 0 of p of m. Sounds weird but yes, this is what we got.