 Hello and welcome to the session. Let us discuss the following question. It says if O be the origin and the coordinates of P be 1, 2, minus 3, then find the equation of the plane passing through P and perpendicular to O P. Now the equation of plane passing through the point x1, y1, z1 and perpendicular to the vector n given by n1i plus n2j plus n3k is given by x minus x1 into n1 plus y minus y1 into n2 plus z minus z1 into n3 is equal to 0. So this knowledge will work as key idea behind this question. Let us now move on to the solution. We are given that plane passes through the point given by 1, 2, minus 3 and we are given that the plane is perpendicular to O P and vector O P is given by position vector of P minus position vector of O. Now position vector of P is given by 1i cap plus 2j cap minus 3k cap and since O is the origin position vector of origin is given by 0i cap plus 0j cap plus 0k cap and vector O P is equal to 1i cap plus 2j cap minus 3k cap. Now the equation of plane passing through the point 1, 2, minus 3 and perpendicular to the vector 1i cap plus 2j cap minus 3k cap is given by using the key idea minus 1 into 1 plus y minus 2 into 2 plus z minus minus 3 into minus 3 is equal to 0 and this is equal to x minus 1 plus 2y minus 4 minus 3z minus 9 is equal to 0 and this is again equal to x plus 2y minus 3z minus 14 is equal to 0. Hence the required equation of plane is x plus 2y minus 3z minus 14 is equal to 0. So this completes the question. I for now take care and have a good day.