 Okay, so let's try this one guys. How many moles of nitrogen gas will be produced from reacting 0.523 kilograms of dinitrogen tetroside? So we've got this reaction equation which tells us, gives us the ratios of the different reactants to products. Of course we've got a 1 to 2 to 3 to 4 ratio here. So 1 equivalence to 2 equivalence goes to 3 equivalence to 4 equivalence. Okay? So, but this tells us the ratio of moles. Okay? And we don't have moles up here, but we can figure out moles from mass values. Okay? So the mass of dinitrogen tetroside that equals 0.523 kilograms. Okay? We're going to have to put this into grams first so we can use the molecular weight of dinitrogen tetroside to figure this problem out. Okay? So we have to remember that 1 kilogram is 1,000 grams. So cancel those two out. And so that equals 523 grams of dinitrogen tetroside. So now we're going to have to use the molecular weight or the molar mass of dinitrogen tetroside and convert that to number of moles. Okay? So dinitrogen tetroside is 14.01 times 2. So we've got 2 nitrogens. Right? So 2 times 14.01. Oxygen, we have 4 of them times 16.00. And both of these are in AMU. So if we just add those numbers up, we get 92.02 AMU. That's the molecular weight of dinitrogen tetroside. Okay? We can assume the molar mass of dinitrogen tetroside is 92.02 grams per mole. But with that information, we should be able to figure out the number of moles of dinitrogen tetroside we have. So let's go ahead and do that. So the number of moles of N2O4 equals 0.523, sorry, we've converted that, 523 grams multiplied by 1 mole over 92.02 grams. Grams cancel leaving us with the number of moles. So just take our calculator, 523 divided by 92.02. That gives us approximately 5.68 moles of N2O4. So to figure out the number of moles of nitrogen, we're not interested in that, but we are interested in the number of moles of nitrogen. But we can use this to get us the number of moles of nitrogen. So we know that we've got 5.68 moles of N2O4. And we know the ratio of moles is 1 to 3 of dinitrogen tetroside to nitrogen. So all we've got to do is multiply this by 3 moles N2 over 1 mole N2O4. Moles of N2O4 can't allow. And that gives us the number of moles of nitrogen. So all we've got to do is multiply that by 3. And we come out with 17.1 moles N2. Of course, we use three sig figs because in the original problem, our numbers only had three sig figs. So that's how you would balance the equation and figure out the number of moles.