 and welcome to the session, I am Deepika here. Let's answer the question, tan inverse root 3 minus secant inverse minus 2 is equal to a pi b minus pi by 3 c pi by 3 and d2 pi by 3. So let's start the solution, principal value branch, an interval minus pi by 2 to pi by 2 is equal to root 3, therefore the value of tan inverse root 3 is equal to pi by 3. Again now we have to find the value of secant inverse minus 2 is equal to secant pi minus pi by 3 which is equal to secant 2 pi by 3. Now the principal value branch of secant inverse is close interval 0 to pi excluding pi by 2 and secant 2 pi by 3 is equal to minus 2, therefore the value of which is equal to minus pi by 3, 2 is minus pi by 3 which is our option b and the correct answer for the above question is b. I hope the question is clear to you while enjoy yourself.