 Hello and welcome to the session. In this session we are going to discuss the following question and the question says that with the help of the given graph, Part A says, find the x-intercept and y-intercept of line n. Part B, find the slope of line n. Part C, find the equation of line n. Part D, find the equation of the line passing through the point with coordinates minus 4, 0 and parallel to this given line. Let us start with the solution of the given question. In this question we are given a graph of a line and in the first part we have to find its x-intercept and y-intercept. Here we can see that this line meets the x-axis at point B and y-axis at point A. Now we know that x-intercepts and y-intercepts are the points where the line crosses the x-axis and y-axis respectively. So here, line crosses the x-axis at the point minus 3, 0, so x-intercept is minus 3. Similarly, line crosses y-axis at the point 0, 2, so y-intercept is 2. Now we move on to the B part of the question. In this part we have to find the slope of this line. Now we see that 0, 2 and minus 3, 0 are the two points that lie on the given line. Let the ordered pair 0, 2 be given by the ordered pair x1, y1 and the ordered pair minus 3, 0 be given by the ordered pair x2, y2. And we know that slope of the line is given by y2 minus y1 whole upon x2 minus x1. So this is equal to 0 minus 2 whole upon minus 3 minus 0 which is equal to minus 2 upon minus 3 and this is equal to 2 upon 3. So slope of this line will be given by 2 upon 3. Now in the next part we have to find the equation of this line. Now we know that slope of this line is given by 2 upon 3 and y-intercept is equal to 2. We know that equation of the line in slope-intercept form is given by y is equal to mx plus c where m is the slope and c is the y-intercept. Now here we have m is equal to 2 upon 3 and c is equal to 2. Now substituting these values in this equation we get y is equal to 2 upon 3 into x plus 2. This implies that y is equal to now taking LCM here we get 2x plus 6 in the numerator and 3 in the denominator which further implies 3y is equal to 2x plus 6. So this is the required equation of line n. Now we move on to the last part of the question which says find the equation of the line passing through the point with coordinates minus 4 0 and parallel to this given line. Now we know that if two lines are parallel then their slopes are equal. So slope of the given line which is equal to 2 upon 3 will be equal to slope of the required line and it is given that this line passes through the point minus 4 0. So let the point with coordinates minus 4 0 be the ordered pair x1, y1. Now we know that equation of the line passing through the point with coordinates x1, y1 and having slope m is given by y minus y1 is equal to m into x minus x1 the whole. Now substituting the values of y1, x1 and m in this equation we get y minus 0 is equal to 2 upon 3 into x minus of minus 4 the whole. This implies y is equal to 2 upon 3 into x plus 4 the whole which further implies 3y is equal to 2 into x that is 2x plus 2 into 4 that is 8. So we have 3y is equal to 2x plus 8 which is the required equation of the line passing through minus 4 0 and parallel to the given line. This is the required solution to the given problem. This completes our session. Hope you enjoyed this session.