 Hello and welcome to the session. In this session we discuss the following question which says construct an equilateral triangle each of whose altitudes measures 5.4 centimeters. Let's move on to the solution now. We would construct this equilateral triangle step by step. First of all, we will draw a line say AB. This is the line AB. Now in the next step we mark any point on the line AB. So this is the point P on the line AB. In the next step we draw PQ perpendicular to AB. So we have drawn this PQ perpendicular to AB. Now in the question we have that the equilateral triangle has altitude of length 5.4 centimeters. So in the next step from the point P we cut an arc of measure 5.4 centimeters on PQ. Let this point be point C where this PC is of measure 5.4 centimeters. Now we know that in equilateral triangle all the angles are of measure 60 degrees. So at point C we will construct an angle PCD equal to 30 degrees and angle PCE equal to 30 degrees. So this angle PCD is of measure 30 degrees and angle PCE is also of measure 30 degrees. So this total becomes 60 degrees. So this triangle DCE is the required equilateral triangle whose altitude that is PC is equal to 5.4 centimeters. So this completes the session. Hope you have understood the solutions for this question.