 Hi and how are you all? I'm Priyanka and let us discuss the following question. It says, solve the inequalities for real x. Now the expression which is given to us is, 2x-1 divided by 3 is greater than equal to 3x-2 divided by 4 minus 2 minus x divided by 5. Now let us start with our solution. On rewriting the given inequality once again, we can observe that we need to take LCM in this question. So the LCM is 60 that is 3 multiplied by 4 multiplied by 5 and on multiplying each term both the sides by 60 now we have 20 bracket 2x-1 is greater than equal to 15 bracket 3x-2 minus 12 bracket 2 minus x. Now on removing the brackets we have 40x-20 is greater than equal to 45x-30-24 plus 12x. After simplification we have 40x-20 is greater than equal to 57x-54. Now on subtracting 57x from both the sides we have 40x-20-57x is greater than equal to 57x-54-57x. After simplification we have minus 17x-20 is greater than equal to minus 54. Now on adding 20 to both the sides we have minus 17x is greater than equal to minus 34. Now on dividing both the sides by minus 17 and changing the sign of inequality or reversing it, we have minus 17x divided by minus 17 is less than equal to minus 34 divided by minus 17. On simplification we have value of x is less than equal to 2. So the solution set is all the real numbers that is less than equal to 2. So an open interval to the closed interval 2. This is our required solution.