 Okay, if we have to discuss about the Lewis structure of CLO4 minus, okay So the first of all we have to find out the number of valence electron the number of valence electron in CLO4 minus is CLO4 minus chlorine has seven electron Oxygen has six so six into four one negative charge we have so plus one for that and that will be 32 Okay, obviously Chlorine is the central atom. So chlorine will write here oxygen Oxygen Oxygen Oxygen around it, right now the next way is what we have to distribute this 30 electron among these atoms, right 30 electron we have to distribute so two four Six eight and then on the outermost electron outermost atom So that the oxate of the outermost atom gets complete. Okay, so each of these oxygen atom Requires six six electron so three lone pair I have given on to the each oxygen atom Correct, if you count the number of valence electron that we have used here It will be six into four twenty four twenty four plus eight is thirty two all these thirty two electron We have distributed right if you calculate the valence like the formal charge on oxygen formal charge on oxygen Each oxygen atom has same configuration the formal charge on oxygen will be what number of valence electron six minus six minus number of Non-bonded electron that is six minus number of bonding electron two divided by two that will be what? minus one each oxygen atom you see has minus one formal charge, right and Each the chlorine atom the formal charge on chlorine if you calculate that will be Seven minus number of non-bonding electron. There is no lone pair on chlorine minus eight by two It is that gives you plus three The formal charge on chlorine is plus three and each oxygen atom has minus one formal charge correct, so since the chlorine is hypervalent atom and we know the Rule of this that if we have hypervalent atom then the charge on the hypervalent atom if hypervalent atom is the central atom Then the charge on the central atom will be the charge on the iron Which is nothing but minus one here or zero, right? So we have to make this charge on chlorine zero to get the exact Loot or structure of this compound, right? So what we do we just shift one of the lone pair from this oxygen atom here to make the bond pair So plus three becomes plus two now again one more lone pair if you shift here Plus two becomes plus one now one more lone pair if you shift then this becomes Zero right now in this is state where these Oxygen atom has two lone pair and this oxygen atom has one lone pair of electron If you calculate the formal charge on chlorine here that will be Seven minus number of non-bonded electron is zero Minus number of bonded electron four plus four eight plus four twelve and twelve plus two 14 so we have 14 by two that gives you zero the chlorine is the hypervalent atom has zero formal charge So it's correct. All these oxygen will have zero formal charge on this oxygen will have Minus one formal charge which you can easily calculate from this Six minus six Right minus two by two is equals to minus one, right? So on this oxygen atom we have minus one formal charge Chlorine will have zero these three oxygen will have zero, right? So the correct Lewis dot is structure of cl o four minus will be This chlorine we have four electron here Four electron here one electron here we have and where we have one pair of electron as bond pair on that oxygen We have three lone pair Here we have two lone pair Here also we have two lone pair and Here also we have two lone pair with man one negative charge onto this Oxygen atom. This is what the Lewis dot structure of cl o four minus. Okay. Thank you