 Hello and welcome to the session. In this session we discussed the following question which says, name the lines of symmetry for the following figures, a kite, a semicircle and a square. First of all let's recall the definition for the linear symmetry and the line of symmetry. A figure is said to be symmetrical about a line if it is identical on either side of the line and this line the line of symmetry acts as of symmetry. This is the key idea that we use for this question. Now we move on to the solution. Let's consider a kite and let's try to find out the lines of symmetry for kite. Consider this kite abcd in which we have ab is equal to ad and bc is equal to cd. Now if you fold the kite along the line ac then the two parts of the kite coincide with each other and as we say that the kite abcd is symmetrical about the diagonal ac and so we have that the kite has only one line of symmetry which is ac in this case. Now next figure that we have to consider is the semicircle. Let's find out the lines of symmetry for the semicircle. Consider the semicircle PQR where we have this OO dash is the perpendicular bisector of the diameter PR. Now if you fold the semicircle along the line OO dash then the two parts of the semicircle coincide with each other. Hence we say the semicircle PQR is symmetrical about the perpendicular bisector of the diameter PR which is OO dash in this case and so we say the semicircle has only one line of symmetry. Now next figure that we need to consider is a square. Let's find out the lines of symmetry for a square. Consider the square abcd and we have PQRS are the midpoints of the sides ab, bc, cd and da respectively. Now we make the diagonals of the square and rejoin the midpoints of the opposite sides. So we have two diagonals of the square which are ac and bd and we have the lines joining the midpoints of the opposite sides the square or sq then we find the two parts the square side with each other. Thus we say that the square abcd is symmetrical about each of the lines ac, bd, pr and sq symmetry which are ac, bd, pr and sq in this case. So this completes the session hope you have understood the solution of this question.