 Hello and welcome to the session. My name is Mansi and I'm going to help you with the following question. The question here says solve each of the following equations. Third equation is x squared plus 3x plus 9 equal to 0. Now before starting with the solution we see the key idea behind the question. Now we see that solution to a quadratic equation ax squared plus px plus c equal to 0 such that a is not equal to 0, a is given by x equal to minus b plus minus under the root b squared minus 4ac the whole divided by 2a. This is equal to minus b plus minus under the root 4ac minus b squared the whole divided by 2a into a. Now we start with the solution to this question. The equation given to us is x squared plus 3x plus 9 equal to 0. Now we find v squared minus 4ac that is equal to 3 square minus 4 into 1 into 9. This is same as minus 27. Therefore x is equal to minus 3 plus minus under the root minus 27 the whole divided by 2 into 1. x is equal to minus 3 plus minus 3 times root 3 ieta divided by 2. Therefore our solution to this question is minus 3 plus minus 3 root 3 ieta divided by 2. I hope you understood the question and enjoyed the session. Goodbye.