 Hello and welcome to the session. In this session we will discuss a question which says that find the area of the shaded region in the figure if AC is equal to 24 cm, DC is equal to 10 cm and rho is the centre of the circle. U is pi is equal to 3.14. Now before starting the solution of this question we should know some results. And that are in a right angle triangle, if we see that pi is equal to AC square is equal to 80 square plus DC square. That is is equal to perpendicular square plus B square. Two of the semicircles equal to 1 over 2 into pi r square. There is the radius of the circle and pi is the constant. And thirdly, area of the triangle is equal to 1 by 2 into base into height. Area of the triangle is 1 by 2 into base into altitude or 1 by 2 into base into perpendicular. Now these results will work out as a key idea for solving out this question. And now we will start with the solution. Now given AC is equal to 24 cm, DC is equal to 10 cm. So given over the centre of the circle AC is equal to 24 cm, DC is equal to 10 cm and U is pi is equal to 3.14. The area of the shaded region. Now UB is equal to 90 degrees because in the semicircle, in the ACB is equal to 90 degrees. In a right angle triangle, by pi square that is DC square plus BC square is equal to 24 cm and BC is equal to 10 cm. So what are these values here? This implies AC square is equal to 24 square plus 10 square. This implies AC square is equal to 576 plus 100. This further implies AC square is equal to 676. This implies AC is equal to 26 cm. The diameter of the circle which is AB is equal to 26 cm. Diameter is AB which is equal to 26 cm. This implies radius which is OA is equal to 26 by 2 which is equal to 13 cm. Now we know that area of the semicircle is 1 by 2 into pi square. So here the area of the semicircle that is this semicircle which is given by 1, 1 is equal to 1 by 2 into pi square. Now here R is 13 cm and pi is 3.14 so it will be 1 by 2 into 3.14 into 13 into 13 cm square. Further this is equal to now 2 into 1.57 is 3 by 1 4 so it will be 1.57 into 169 cm square which is equal to 265.33 cm square. Now area of the triangle ACV is equal to 1 by 2 into BC into HAC is equal to 24 cm and BC is equal to 10 cm. So what are these values here this will be equal to 1 by 2 into 10 into 24 cm square which is further equal to 2 into 5 is 10. So this will be equal to 5 into 24 120 cm square. Now the shaded region is equal to semicircle 1 semicircle. These values here this will be equal to 265.33 cm square minus 120 cm square which is equal to 135.33 cm square. The shaded region is equal to 135.33 cm square. So this is the solution of the given question and that's all for this session. Hope you all have enjoyed this session.