 Hi and welcome to the session. I am Deepika here. Today let's discuss the question constructor 3 by 4 matrix whose elements are given by aij is equal to 2i minus g. Let us start the solution. Solution in general a 3 by 4 matrix is given by a is equal to a11, a12, a13, a14, a21, a22, a23, a24, a31, a32, a33, a34. aij is given as twice i minus j where i is equal to 1, 2, 3 and j is equal to 1, 2, 3, 4. Now a11 is equal to, put i is equal to 1 here and j is also equal to 1. We get a11 is equal to 2 into 1 minus 1 which is equal to 1. Again a12 is equal to i is equal to 1 and j is equal to 2. We get 2 into 1 minus 2 which is equal to 0. Again a13 is equal to 2 into 1 minus 3 which is equal to minus 1 and a14 is equal to 2 into 1 minus 4 which is equal to minus 2. Now a21 is equal to 2 into 2 minus 1 which is equal to 3 and a22 is equal to 2 minus 2 which is equal to 2. Again a23 is equal to 2 into 2 minus 3 which is equal to 1 and a24 is equal to 2 into 2 minus 4 which is equal to 0. Again a31 is equal to 2 into 3 minus 1 which is equal to 5 and a32 is equal to 2 into 3 minus 2 which is equal to 4 and a33 is equal to 2 into 3 minus 3 which is equal to 3 and a34 is equal to 2 into 3 minus 4 which is equal to 2. So the matrix A is given by is equal to 1 0 minus 1 minus 2 3 2 1 0 again 5 4 3 2. Hence we have constructed a 3 by 4 matrix whose elements are given by Aij is equal to 2 i minus j and the answer is A is equal to 1 0 minus 1 minus 2 3 2 1 0 5 4 3 2. I hope you have enjoyed the session. Bye and take care.