 Hi and welcome to the session. Let us discuss the following question. Question says, find the Cartesian equation of the following plane. This is the given plane. First of all, let us understand that if this is the vector equation of the plane, then Cartesian equation of this plane is AX plus BY plus CZ is equal to D, where A, B and C are the direction ratios of the normal to the plane. This is the key idea to solve the given question. Let us now start with the solution. Now given equation of the plane is r vector dot 2i plus 3j minus 4k is equal to 1. Now clearly we can see this equation is in this form. Now comparing these two equations, we get value of A is equal to 2, value of B is equal to 3, value of C is equal to minus 4 and value of D is equal to 1. Now we can find Cartesian equation of the given plane by substituting values of A, B, C and D in this equation. So we can write Cartesian equation of the given plane is 2x plus 3y minus 4z is equal to 1. So this is our required answer. This completes the session. Hope you understood the solution. Take care and have a nice day.