 Hello and welcome to the session. In this session we will discuss the following question which says, find a point on the base of a scaling triangle equidistant from its sides. Before we move on to the solution, let's discuss one theorem which says that the focus of a point equidistant from two intersecting which bisect the angle between straight lines. The key idea that we use for this question. Let's proceed with the solution now. With this triangle ABC, we have a scaling triangle. We are supposed to find a point on the base of the scaling triangle which is equidistant from its, that is, we are supposed to find a point on the base BC such that that point is equidistant from the sides AB and AC. From the key idea we know that the focus of a point equidistant from two intersecting straight lines consists of a pair of straight lines which bisect the angle between two given straight lines. From this key idea we also conclude that every point equidistant from two intersecting straight lines line on the angle bisector being the given two intersecting straight lines. On the base BC which is equidistant from the sides AB and AC, what we do is we draw the angle bisector the angle BAC. So we have drawn this AX as the angle bisector of angle BAC such that it meets the base BC as point P. That is, AX is the angle bisector of angle BAC which meets the base BC triangle ABC P. So this means the angle bis, angle BAC. And since we know that every point bisector between the two intersecting equidistant from the given lines ties on the angle bisector of angle BAC thus we can say that the point equidistant from the sides AB and AC of triangle ABC. Hence required point on the base BC of scaling triangle ABC which is equidistant AC of triangle ABC. So this completes the session. Hope you have understood the solution of this question.