 Hi and welcome to the session and Priyanka and let us discuss the following question it says in figure 7.49 angle B is less than angle A and angle C is less than angle D. Show that AD is less than BC. Now this is figure 7.49 which we need to refer for the above written question. It says that angle B is less than angle A and angle C is less than angle T. Now we need to show that AD is less than BC. So let us start with our solution. Angle B is less than angle A and angle C is less than angle D. This is given to us in the question. We need to prove or we need to show that AD is less than BC. Let us start with our proof. Now we are given that angle B is less than angle A. We can write that therefore OA is less than OP. Giving the reason that because sides opposite to greater angle is longer. So the side opposite to the greater angle that is angle A is OB. So therefore OB is greater than OA. Similarly angle C is less than angle T. So we can write therefore OD is less than OC. Now let this be the first equation and this be the second equation. On adding 1 and 2 we have OA plus OD is less than OB plus OC. Now as we can see OA plus OD will give us AD and OB plus OC will give us BC. So we can write that this implies that AD is less than BC. So this is what we need to hence showed that AD is less than BC. This completes the question that was given to us. I hope you enjoyed the session. Bye.