 Hi and welcome to the session. I am Asha and I am going to help you with the polynomial question which says if z1 is equal to 2 minus iota and z2 is equal to 1 plus iota, find modulus of z1 plus z2 plus 1 upon z1 minus z2 plus iota. Any complex number z, this is of the form a plus iota b. Modulus of z is equal to root over a square plus b square modulus of z1 upon z2 is equal to modulus of z1 upon modulus of z2. So, these are some ideas with the help of which we will find the value of this modulus. So, this is a t idea, not a solution. First let us find the value of z1 plus z2 plus 1 upon z1 minus z2 plus iota and then we will find its modulus. So, z1 is 2 minus iota plus z2 is 1 plus iota plus 1 upon in the denominator is z1 plus 2 minus iota minus of z2 1 plus iota plus i. Now, minus iota plus iota cancels out and we have 2 plus 1 is 3 3 plus 1 4 upon in the denominator we have 2 plus iota minus iota cancels out and we have minus 1 minus iota. This further equal to 4 upon 1 minus iota. Therefore, modulus of z1 plus z2 plus 1 upon z1 minus z2 plus iota is equal to modulus of 4 upon 1 minus iota which is further equal to modulus of 4 upon modulus of 1 minus iota this is by a t idea. This further equal to numerator we have root over 4 square upon the denominator modulus of 1 minus iota will be 1 square plus 1 square which is further equal to 4 upon root over 2. Let us rationalize it by multiplying the numerator and denominator by root 2. We have 4 root 2 upon 2 canceling the common multiple we have 2 root 2 the value of modulus z1 plus z2 plus 1 upon z1 minus z2 plus iota is equal to 2 root 2. So, this completes the solution hope you enjoyed it take care and have a good day.