 Hello and welcome to the session. In this session we will discuss a question which says that construct a triangle ABC in which VC is equal to 8 centimeters, angle D is equal to 45 degrees and angle C is equal to 30 degrees. Construct another triangle similar to triangle ABC such that its sides are 3 by 4 of the corresponding sides of triangle ABC. And now we will start with the solution. Now in the question we have to construct a triangle ABC in which BC is equal to 8 centimeters, angle B is equal to 45 degrees and angle C is equal to 30 degrees. Now we will start with the steps of construction. In the first step draw a line segment BC is equal to 8 centimeters. So here we have drawn a line segment BC which is equal to 8 centimeters. Now in the second step construct an angle of 90 degrees at the point B. So here we have constructed an angle of 90 degrees at the point B. And then bisect this angle that is the angle of 90 degrees such that angle ABC is equal to 45 degrees. Now here we have bisected the angle of 90 degrees such that angle ABC that is this angle is equal to 45 degrees. Now an angle of 60 degrees at the point C. Now we have constructed an angle of 60 degrees at the point C and bisect this angle that is the angle of 60 degrees such that angle QCB is equal to 30 degrees. Now we have bisected the angle 60 degrees such that angle QCB is equal to 30 degrees. And in the next step name the point of intersection of the A BP and CQ such that the ABC is the required triangle. Now here we have named the point of intersection of the CQ and BP as A and the triangle ABC is the required triangle in which BC is equal to 8 centimeters and the B is equal to 35 degrees and angle C is equal to 30 degrees. And now we have to construct another triangle similar to triangle ABC such that its size are 3 by 4 of the corresponding size of triangle ABC. Now in the next step draw any way BX making an acute angle with BC opposite to vertex. So this is the way BX which is making an acute angle with the side BC and it is on the opposite side to the vertex A. Now in the next step locate 4 that is the greater of 3 and 4 in 3 that 4 so we have to locate 4 points B1 B2 B3 B4 so that BB1 is equal to B1 B2 is equal to B2 B3 is equal to B3 B4. So we have located 4 points that are B1 B2 B3 and B4 on the way BX such that BB1 is equal to B1 B2 is equal to B2 B3 is equal to B3 B4. Now in the next step join B4 C and draw a line through B3 that is the third point as 3 being smaller of 3 and 4 in 3 by 4 so we will join B4 C and draw a line through B3 which is parallel to B4 C to intersect BC at C dash so we have joined B4 C and draw a line through B3 which is parallel to B4 C to intersect BC at this point that is the point C dash now in the next step draw a line through C dash which is parallel to the line C A to intersect BA at A dash a line through C dash which is parallel to the line C A BA at A dash so we have C dash A dash parallel to C A and then the triangle A dash B C dash is the required triangle therefore triangle A dash BC dash is the required triangle such that its sides are of the corresponding sides of the triangle ABC so this is the solution of the given question and that's all for this session hope you all have enjoyed this session