 Hello and welcome to the session. Let us discuss the following question. It says integrate the following function The given function is x upon e to the power x square. Let's now move on to the solution and let i be the integral x upon e to the power x square dx Now we see that the derivative of x square is 2x which contains x So we put equal to x square So dT is equal to 2x and this implies x dx is equal to dt by 2. Now x dx is dt by 2 and x square is t. So Substituting all these values in the integral the integral becomes 1 upon e to the power t dt by 2 Which is again equal to 1 by 2 into integral of e to the power minus t dt Now The value of the integral is e to the power minus t upon minus 1 plus 3 So this is equal to minus 1 by 2 Into e to the power minus t plus c which is again equal to minus 1 by 2 Substituting the value of t it becomes e to the power minus x square Plus c which is again equal to Minus 1 by 2 into e to the power x square plus c Hence the integral of the given function is minus 1 by 2 into e to the power x square plus c and This completes this question and the session by for now. Take care. Have a good day