 motion under gravity right down is motion under the influence of how much is that gravity m into g that is g, m into g is the force, so if object constant ok direction motion right direction is down which is constant and right to the easy ok this acceleration if observations from this topic under the gravity motion to be constant which is g which is 9.8 meter per second square unless taken otherwise ok. Now this chapter is motion in one dimensional one dimension ok so when the stationary net force is 0 when I release alright so how should I release it or how should I throw it so that it moves in a straight line cross straight line or in an object from here g is g I don't know root to s by g square or t you will get to h by g understood ok what time it takes to be in terms of g and h just write down the equation initial and final equation h if you take it down initial classes ok so use s equal to ut plus half at least this is minus you understood another question