 Okay, so this is going to be the anphromosacinamide bromination of the benzylic position here. And this is going to be a radical reaction. You can see it's initiated through heat or light. So what we'll do is, you guys remember, single electron transfers for radical reaction, right? So bond homolysis, things like that. The first thing you need to know is the structure of MBS. So I'm going to erase because now that we know what we're getting to, right? So MBS has a particularly labial bond. And it's this M-V-R bond. Remember what we talked about earlier about orbital overlap between big atoms and small atoms, right? And so they're going to have a bad orbital overlap there. And remember, bromine is so big that it doesn't mind really being by itself. Not to mention that you've got these electron withdrawing groups, alpha to the nitrogen there. So what will happen is when you take this compound MBS and you subject it to heat or light, a small, very, very small percentage of it will bond homolyse, OK? So for those of you who don't remember what bond homolysis is, it means that one electron goes one way and the other electron goes the other way. And again, this doesn't happen to any appreciable extent. But because radicals are so reactive, once this occurs, the reaction will progress. So remember, that's your initiation step there. So what we're going to recall, if you recall from our discussion last time, is that benzylic hydrogens or benzylic protons are particularly labial due to the fact that there's a lot of resonance structures that you can make if you make a radical at that position. So there's a variety of mechanisms that you can imagine. The most common one is to think of actually two BRs coming back together in BR2 like this. So that's the first step, OK? And then this BR has come from another one of these. And then what will happen here is you'll have the next step, reacting this again with light or heat to bond homolysis again. So you can think of it stopping here and using that BR. Or you can do this, because this is going to produce the same thing, two BR radical. So either way you want to look at it, I would suggest just stopping here. The only reason I mentioned this is because if you look at the literature, they're going to talk about this. And you might be as confused as to why they're doing it. For me, I don't really mind too much if you just stick with this guy here and start the reaction. So can I raise this part here? So this is the guy we're going to be reacting with, this bromine atom, which is a radical. And we've got that benzylic hydrogen that's easy to abstract. So we've got that radical there. This is going to be a propagation step. We're propagating from a radical to another radical. And remember bond homolysis, this is only one electron. Got to show the other electron like that. Now I'll leave it to you guys to draw the resonance structures of this benzylic radical. In fact, we'll do some of those later, what I'm saying. But I would like you to justify why this thing in your own head is fairly stable relative to a primary radical or a secondary. Well, anyways, remember from that other step, we made another Br radical. So we had two Br radicals. So here, with that, we're also making HBr. Remember, we talked about two NBSs breaking apart, then the two bromines coming together, then those two bromines splitting back apart, right? So if you think about all of that, we still really have this radical species. What this is going to do is going to do your termination step there. So there's your organic product. Benzylic position has been brominated. We still have this GHBr, which, again, has a very small atom attached to a big atom, right? So those bonds are very labile. We know that. Bond dissociation at energy is very low, if you will. So the other NBS molecule, just where your hand was, it felt like they were at the wrist at all. OK, so we're just going to do that reaction again, right? When we do that, we get that. And then this does this reaction like this. And then you've got your two Br radicals again that are going to do that coupling and then breaking apart, OK? So again, this part of the mechanism really isn't as crucial to getting your product. Because of course, what are we going to get here? We're just going to get this succinimide, like we said, the two Br radicals that will couple together. And then produce this thing after light shines on them and break apart, OK? So is everybody cool with this mechanism? Is there any questions about it? We really just did the edge there. Again, I'm not really so concerned with you guys thinking about breaking apart and then coming back together. I want you to understand that it's this thing that's doing the initial hydrogen abstraction and then the other one that's coming and being the termination step, OK? Any questions on this guy?