 Hello and welcome to the session. In this session we discussed the following question it says draw a circle of radius 3.5 cm and take a point A outside it. Without using the center of the circle draw two tangents to the circle from the point A. So we have to do this construction in which we have a circle of radius 3.5 cm and a point A outside the circle and from this point A we have to draw two tangents to the circle without using the center of the circle. Let's see how we can do this. We will do this construction step by step. So our first step of construction would be draw a circle of radius 3.5 cm and take a point A outside it. This is the circle of radius 3.5 cm and we have taken a point A outside this circle. In the next step to the point A we draw a secant ABC to intersect the circle B and C. So this is the secant ABC which intersects the circle at points B and C. Then next we produce VA to a point P such that is equal to AB. So this VA is produced to a point P such that we have PA is equal to AB. Then our next step of construction is draw a semicircle PC as the diameter. So we have drawn the semicircle taking PC as the diameter. Then we draw AD perpendicular to PC intersecting the semicircle point D. So this AD is perpendicular to PC. Now next step is with A as the center AD as the radius draw arcs at the circle and T dash. As the center and radius equal to AD we have drawn these two arcs intersecting the circle at points T, T dash. Now next we join AT and AT dash. So we have joined AT and AT dash. AT and AT dash are the required tangents. This is a construction where we were given a circle of radius 3.5 cm and a point A outside the circle. From this point A we have drawn two tangents AT and AT dash to the circle without using the center of the circle. So this completes our session. Hope you have understood the solution of this question.