 Hello and welcome to the session. In this session, we will discuss the following question and the question says, consider the integration 2 plus x is greater than 5, obtain the solution set for the replacement sets given by, first part is, e is equal to the set containing the elements 0, 3, 6, 9, 12 and 15, second part is, q is equal to the set containing the elements minus 1, 0, 1, 2, 3 and 4, third part is, r is equal to the set containing the elements 0, 1, 2, 3. Before we start solving the question, let us first recall, what is a replacement set? Now, a replacement set is a set that may contain elements which are in solution set of the inequality or we can say that the unknown variable in the inequality can be substituted by some elements of the replacement set such that the in equation is satisfied. Now, this is a key idea for this question and using this key idea, we shall solve the question. Let us start the solution now. First, let us find the solution set of the given in equation. We have 2 plus x is greater than 5, now we subtract 2 from both the sides. So, we get 2 plus x minus 2 is greater than 5 minus 2. Note that here, the inequality remains the same because same number is being subtracted from both the sides. So, this implies x is greater than 3. Now, consider the first replacement set which is the set P is equal to the set containing the elements 0, 3, 6, 9, 12 and 15. So, the elements in P which are greater than 3 are 6, 9, 12 and 15. Thus, x can be substituted by these values in the given in equation. Hence, the solution is x is equal to 6, 9, 12, 15. Now, consider the second replacement set which is q is equal to the set containing the elements minus 1, 0, 1, 2, 3 and 4. Now, here only 4 is greater than 3, hence the solution is x is equal to 4. The third replacement set is r is equal to the set containing the elements 0, 1, 2 and 3. We can see that there are no elements greater than 3 in r, hence the solution is the empty set 5. So, with this we end our session. Hope you enjoyed the session.