 Hi and welcome to the session. I am Shashi and I am going to help you to solve the following question. Question is using elementary transformations, find the inverse of each of the matrices if it exists. The given matrix is 2357. Let us now start with the solution. First recall, let us assume A is equal to matrix 2357. Now to find A inverse by using the method of elementary row transformation we will write A is equal to IA where I is the identity matrix or we can write matrix 2357 is equal to 1001 matrix multiplied by A. Now we will apply sequence of row operations simultaneously on the matrix A on left hand side and the matrix I on the right hand side till we get the identity matrix on the left hand side. Now to make this element equal to 1 we will apply on R1 row operation 1 upon 2 R1. So we can write applying R1 row operation 1 upon 2 R1 we get 1 3 upon 2 5 7 matrix is equal to matrix 1 upon 2 0 0 1 multiplied by A. Now to make this element equal to 0 we will apply on R2 row operation R2 minus 5 R1. So we can write applying on R2 row operation R2 minus 5 R1 we get matrix 1 3 upon 2 0 minus 1 upon 2 is equal to matrix 1 upon 2 0 minus 5 upon 2 1 multiplied by A. Now to make this diagonal element equal to 1 we will apply on R2 row operation minus 2 R2. So we can write applying row operation minus 2 R2 we get 1 3 upon 2 0 1 is equal to matrix 1 upon 2 0 5 minus 2 multiplied by A. Now to make this element equal to 0 we will apply on R1 row operation R1 minus 3 upon 2 R2. So we can write applying row operation R1 minus 3 upon 2 R2 we get matrix 1 0 0 1 that is identity matrix is equal to minus 7 3 5 minus 2 multiplied by A. Now clearly this is identity matrix so we can write I is equal to A inverse multiplied by A. Now comparing the two expressions we get A inverse is equal to this matrix so we can write A inverse is equal to matrix minus 7 3 5 minus 2. So the required inverse is given by the matrix minus 7 3 5 minus 2 this is the required answer hope you understood the session take care and goodbye.