 Let's try this one now. Very similar to emin formation, but it's now enamine formation. En, right? En, like alkene, amine, enamine, okay? So all these names are so clever, right? So again, very similar to emin formation. The only difference is instead of having a primarium emine, right? We have a secondary emine, okay? So when that happens, we're going to make an enamine instead, okay? So I'm going to erase all of this because I know what we're going to do. Everybody write down all that stuff, okay? So first thing you have really want to realize, honestly, is that this molecule is more basic than this molecule, okay? So the first proton transfer from sulfuric acid is going to go onto this molecule here. It doesn't matter all that much, but it's good to know, okay? Because the first step of the mechanism is going to be protonation of the So, it's going to make more product. So we've got this plus now, the conjugate phase of sulfuric acid, okay? Not really that big of a deal because we're just going to use that as the acid, okay? The clotrimerium emin, that's part of the protonated emine as the acid. I don't need to put a CH3. So first step, protonation of the ketone oxygen. And again, like I said, if you had done this directly with sulfuric acid, it was not like it would take off any points. It's just good for you guys to think about which one's more basic, you know? And again, this is going to be an equilibrium. All acid-base reactions are in equilibrium. And then, of course, regenerated dimethylamine. Remember, this thing's now, remember, what we've been calling our super electrophile, okay? Let's actually write it down, finally. So whenever you see something like this, whenever you see that, definitely. But whenever you see something like this, right, going to be attacked, okay? Anything that has that carbonyl oxygen with a plus, it wants to be attacked because it wants to get rid of that problem. So that's our super electrophile that we've been calling. Very good nucleophile. It's going to attack. I don't need to draw that resonance structure, right, anymore. You guys have gotten that resonance structure of the super electrophile. Again, in equilibrium. So you've got some sort of base in there, okay? Whether it's the initial starting material, some excess water, some other things that are in there, the conjugate base of the acid, sulfuric acid, anything, okay? It could be in there. In fact, it could be another one of these molecules, okay? So what's going to happen is you're going to have let's just say water is the base, okay? Or let's just say any old base is the base, okay? Because we don't really know what it's going to be. It could be a variety of things. That's going to remove that proton there. Again, it's an acid-base reaction, so it's going to be in equilibrium. You'll see again, just like always, the driving force of these reactions is going to be formation of one of these small molecules. We got that now. Is everybody okay with that? That's again, so I don't have to say I'm going to protonate this, erase this thing, and then do it again. Like you guys don't like me to do, when I say it. Can I just erase this part? Okay, so now reprotonation. So that's that protonation, deprotonation, reprotonation step. Again, in equilibrium. Okay, so this is the step that pushes the reaction forward, right? Why? Because we're going to be making water. Okay, that's a very stable molecule. So remember, kick out the leaving group, always. Okay, it's always this kick out of the leaving group. And what kind of arrow are we going to have here? A straight forwarder. Again, there is a chance that water will come back and attack, but it's good to think of this as the driving force step, because why? Because this is where we're going to be removing that water, okay, if we've got a dry insult or something. So if you really wanted to, you could put that minus H2O to emphasize that you're removing that water, but it's not necessary. Showing this step, showing this is good enough. So what are we going to make? Not yet. We're very close to it though. So we're going to remove that water. But this is not, this is not something that we can isolate. Okay, we could isolate this, but it would be more difficult, and it's not an enemy, right? We'd have to isolate it as a salt or something. But we've got starting material, which is a base. We've got this amine, which is a base. We've got a lot of bases in here, okay? So we're just going to put another just general base, okay? Probably the same thing here. And it will actually remove the alpha proton here. Okay? That alpha proton becomes very acidic. Why? Because that nitrogen, just like over here, where we have that super electrophile, it does not like to have that positive charge, okay? So it wants to have something that will make it get rid of that positive charge. So if you've got a base in there, we'll deprotonate that alpha proton there. Those electrons will move to there. Those electrons will move to there. And now, what do we got? Yeah, our final problem. So don't jump to the conclusion that you're making the amine. If it were an amine, right, we would have been done at that point, right? But since it's the amine, because we don't want that positive charge there. And then of course the HV plus, this will be washed away when you extract this from your reaction. So that's your problem. So that's an amine formation. So is everybody cool with that? So in this case, remember, you have to have an aldehyde or a ketone in a secondary amine. Are there any questions? Definitely not, huh?