 Hello and welcome to the session. Let us discuss the following question. It's says in figure XP and XQ are two tangents to a circle with center O from point X outside the circle ARB is a tangent to the circle at R Right through that XA plus AR is equal to XB plus BR. So let's now move on to the solution Let's first write what is given to us We are given that XP XQ and ARB are the three tangents to the circle and let's now write what we have to prove You have to prove that XA plus AR is equal to XB plus BR So let's now start the proof Now BR is equal to BQ Similarly AR is equal to AP This is because tangents drawn from an external point equal So BR is the tangent drawn from B Similarly BQ is the tangent drawn from B So BR is equal to BQ and similarly AP is equal to AR Now similarly XP is equal to XQ again by the same reason So we have XB can be written as XA plus AP and XQ can be written as XB plus BQ now Let's name this as one and this is two Now AP is equal to AR So we have XA plus AR is equal to XB Plus BQ BQ is same as BR just from One and two so we have proved that XA plus AR is equal to XB Plus BR So this completes the question and the session. Bye for now. Take care. Have a good day