 Hi and welcome to the session. Let us discuss, it says solve the inequality 3 to minus x greater than equal to 2 1 minus x for real x. Proceeding on with the question, first of all here we need to remove the brackets. And on removing the brackets we get 6 minus 3x is greater than equal to 2 minus 2x. On subtracting 6 from both the sides we have 6 minus 3x minus 6 is greater than equal to 2 minus 2x minus 6. After simplifying we have minus 3x is greater than equal to minus 2x minus 4. Now on adding 2x both the sides we have the inequality as minus 3x plus 2x is greater than equal to minus 2x minus 4 plus 2x. After simplification it becomes minus x is greater than equal to minus 4. On multiplying both the sides by minus 1 we have it as minus x getting multiplied by minus 1. And we know that according to rule 2 when we multiply or divide by a negative number then the sign of inequality gets reversed. So here it will be now less than equal to minus 4 multiplied by minus 1. The answer will be x is less than equal to 4. So as x is a real number the solution set consists of all real numbers less than equal to x. So that means 4 is included in this interval and minus infinity is having an open interval at inside. So bye for now.