 Hello friends, let's solve the following problem of probability. It says, a letter is chosen at random from the word assassination. Find the probability that the letter is a vowel and a consonant. Before moving on to the solution, let us learn the formula for the probability of any event E. Probability of any event is given by the number of outcomes favourable to E upon the total number of outcomes. It will be the key idea. Let us now move on to the solution. So the given word is assassination and the number of letters, the number of letters in this word 13 1 2 3 4 5 6 7 8 9 10 11 12 and 13 and the first part we have to find the probability of choosing a vowel. So here E is the event of choosing a vowel. There are six vowels in this word 1 2 3 4 5 and 6. So the number of outcomes favourable to E equal to 6. So the probability of choosing a vowel equal to 6 by 13 that is the number of outcomes favourable to E upon the total number of outcomes. Here the total number of outcomes are 13 as the number of letters in this word is 13. Now there are seven consonants. So the number of consonants is equal to 7. So the E is the event of choosing a consonant number of outcomes favourable to E equal to 7. So the probability of choosing a consonant is equal to 7 by 13 that is the number of outcomes favourable to E upon the total number of outcomes. So the probability of getting a vowel is 6 by 13 and probability of choosing a consonant is 7 by 13 and this completes the question. Bye for now. Take care and have a good day.