 Hi and welcome to the session I am Deepika here. Let's discuss the question. Differentiate the following with respect to x e raised to power sin inverse x. So let's start the solution. Here we will use a chain rule that y is equal to e raised to power t where t is equal to sin inverse x. Therefore dy by dt is equal to e raised to power t and dt by dx is equal to 1 over under root of 1 minus x square. Therefore dy by dx is equal to dy by dt into dt upon dx. Now we have dy by dt is e raised to power t and dt upon dx is 1 over under root of 1 minus x square. The denominator is not defined when x is equal to plus minus 1. So x should not be equal to plus minus 1. Substitute the value of t here. We have dy by dx is equal to e raised to power sin inverse x upon under root of 1 minus x square and x belongs to open interval minus 1 to 1. Hence the answer for the above question is e raised to power sin inverse x upon under root of 1 minus x square where x belongs to open interval minus 1 to 1. I hope the solution is clear to you. Bye and take care.