 Okay students we will wait for one minute then we'll start so can we start one minute just one minute Okay, now who has not joined Yes, yes, good and just one minute. Just one minute. Please please Okay, fine. Now we are going to start up with all set ready So today is the new chapter that is is matter around us. Yeah, let's see what you are going to get in this paper Your first question is in front of you first question is in front of you 40 gram of common salt is dissolved in 320 grams of water the mass percentage of salt is mass percentage of salt is read the question carefully then do it very easy question but Yes, very easy do it Get the full marks. I am expecting 100 percent, you know, I've not seen a curve in which like I've not seen any graph in which There are rest of the bars are zero and the one bar is showing hundred percent. I've never seen that thing. So Can you show that in today's center mark? But in chemistry doesn't it didn't happen in chemistry. I mean, so Yes, tell me So this was in this no sir, I'll tell you yes, sir. Now I Sir, no, I'll tell this question was there in the textbook, right? I don't know Yes, what happened Sir, it is the textbook this question Okay, I don't I don't know from it is there in the textbook or not But I got it from like I have so some so from Okay, okay fine. No problem. Let's go. So it's still 25 more than More than 50% of you have done this question wrong. It's very easy. So Just I'll take your one minute to explain this Okay, not much. Just one minute. So it is see Okay, first question is in front of you. So Christian says that If you read the question it is like percentage mass by mass they ask what is the percentage of the solution? The salt is given to you. That is the one minute 40 gram is given to you and it's a hundred gram of the solution Just One minute Okay, please please mute your mics That's why you should spend time on the question. Okay, so 40, okay, I'll explain after this Okay, don't worry one minute. I'll explain this question. Just go to the next one. Then we'll spend then we'll see Okay, first see the result. What is the? leaderboard says Okay, so the leaderboard is Saying that Rishab NPS INR is leading I think Okay, fastest gentle Bishop both have done at the same speed. Okay, fine. We'll discuss that just after the Next question. Okay. Are you ready all of you? We'll discuss that question. Don't worry. Yes coming to the next question it says the mixture of sulfur and carbon disulfide is mixture of Sulfur and carbon disulfide is what? You have to tell the answer in this Hydrogenous and shows tinder effect homogenous and shows tinder effect Hydrogenous and so does not show tinder effect homogenous and does not show tinder effect. I Hope most of you get it correct. Let's see. Okay fine, Monisha Monisha, but I think I explained this Okay, fine. That is the carbon and self carbon disulfide and sulfur What is going to come? I? Told you somewhere in the class Okay, please Monisha. What you are typing? Okay, so the answer is there carbon disulfide and sulfur forms us colloidal solution and colloidal solutions are always had Hydrogenous colloidal solution are heterogeneous, but shows tinder effect. So answer is a very good students Moving to the next one. So who are who is letting the sea? Okay, so answer is Rohan is leading PRM 9 very good Rohan Moving to the next question The tincture of iodine has an antiseptic property. This solution is made of dissolving Tincture of iodine. It is also there in NCRT those who are saying so it is there in the book or somewhere else It is also there in the NCRT. Tincture of iodine has antiseptic property and You know this I also explained in class that you must have seen the tincture of iodine in the your Medical room you must have seen that. Oh Thanks, it was just 30 seconds and it is nothing but iodine and alcohol mixture very good mixture of iodine and alcohol Very good students moving to the next question Moving to the next first. We'll see the leaderboard. I know you people are just Waiting for leaderboard to see the leaderboard now KRM NPS KRM is there. Oh, no R&R NPS is reading very good Nishan Fastest very good. Let's see the next question The next question is to substance read the question properly to substance A and B were made to react to form the third substance A to B according to the following 2a plus B gives A to B Which of the following statement concerning these reactions are incorrect? Product A to B shows the property of substance A and B The product will always have fixed composition Product so far cannot be classified as compound the product so far is an element so I Think 24 have answered as of now Monisha, please stop Forwarding this okay, so what is GI GI I didn't understand GI IG Okay, okay, so okay got it Stop telling Yes, so you have 16 more seconds, you know A to B it's forming from A and B Okay, and the answer of this question is product A to B shows the property of substance A and B The product will always have a fixed composition. Oh my gosh, so it times up 23 students have done this right. Let's see. What is this Christian? Why you people have made mistake in this? So if you open the fourth Christian support Christian says that The two substance A and B were made to react to form a third substance third substances forming no problem and it is nothing students A plus B A plus B. Let's say 2 a plus B gives you a to be a to be is nothing but a compound and a compound does not have a Properties of its elements. So a to be shows the property of substance A and B. No Just product will always have a fixed composition. Yes, the product so far cannot be classified as a compound No, the product so far is an element. No, they have asked you incorrect Right now incorrect. So these three are incorrect one three and four answer is C Hope hope you understood this Yes, and and again, I'll go to the question number one Question number one is this 40 gram of common salt is dissolved 40 gram of common salt I will have to just take your one minute 40 gram of common salt. This is solute and 320 gram is the water That is solvent The mass percent percent weight by weight is the mass percent is mass of solute mass of solute Divide by mass of Solution Most of you must have made mistake in this formula. You must have written mass of solvent So what you are going to write mass of solute is 40 divide by three eight three sixty into 100 This is the answer Understood Okay, this is very important. This concept is used in other questions. Also, that's why I have explained it If anyone has any doubt, please ask now Okay, now so coming to the next question So this is the next question first. We'll see the leader board students I'm eagerly waiting to see that So I'd like all are giving the right answer in one question. I'm eagerly waiting for that moment Okay, and be a siren or Nishant is still leading Nishant be careful read the question properly then answer Okay, and then now you have next So it's not showing the question What is this? No question What is the question? What is the question? What is the question? No question So No question No question in the folder Okay, fine. I'll leave it Can we mark something? Okay, okay, no problem. No problem. Don't mark anything Mark, don't mark We are moving to the next question Just leave the question Don't worry, don't worry. Move to the next question Why are you worried? Sir, how do you get points? Sir, they got points. That's not what I've just guessed So it should be a read It should be a read Go back and tell us the right answer Okay, fine By two places Okay, moving to the next question Be ready for that A student carefully observed the colloidal of starch in water Student carefully observed the colloidal of starch in water Human blood and cow milk On the basis of observation He made certain conclusions and even below Choose the wrong conclusion about the colloidal solution Very easy question Okay Student's question number fifth was very important I will show you at the end of the quiz Don't worry Okay So, okay, fine Moving to the answer Answer of this question is Oh, what the student have only marked it right Okay, just let me see Okay, fine So let me go to the question We'll discuss how it happened How you can solve this I think it's a question number six Okay, moving to the question number six First I'll explain you Okay, a student carefully observed the colloidal I think most of you have made mistake because you must have not read this Choose the wrong conclusion Choose the wrong conclusion And you know all this starch in water Human blood and cow milk All these are the colloidal solution All these are the colloidal solution Okay B is wrong Component or separatory by Okay, one minute I got the answer right Okay, translucent It is not C So you can't filter milk using a filter paper One minute Components can be separated by ordinary filtration Ordinary filtration Can be separated by ordinary filtration No Okay, homogeneous and stable Okay, so B and C Both are wrong Okay, fine We will ignore this question C You can go back Go back four times Go back four times Yes, sir Go back four times And tell us the correct option for the previous question And then we can mark One minute Go back then Sir, go back four times Okay, fine Wait I'll explain you the previous question also Just give me one second Okay, this is the second time This was the result This was the third time This is what you were saying And this is the fourth one Yes Okay, yes Now, what do you want to say Should I move to the next one Now you can start Then it will start from the start So can you tell the right answer for this question Okay, question number five answer you want Okay, fine I'll tell you Question number five right answer Yes, yes, one minute Answer of question number five is B Do it, but I will explain you That is a very important question B for Bombay B Okay, mark it B Mark it B Just a minute Sir, I wasn't able to vote in time Sir, you have to go back You have to go back and wait Okay, just a minute Sir, now go back and then you have to wait Okay, but still This is the previous result, yes Okay, fine After that we have to go to the next step Okay, just a minute Now it's over I'm moving to the next question Yes Yes, sir, you have to mark B, right? Yes, B Sir, but it's already marked Sir, but it is not possible to vote again You can't maybe not vote in time You have to vote in time Okay, okay So you have to go back and wait So proceed sir, it's fine Okay, okay, leave it Move to the next question Please don't waste time Okay, so So what about this? Okay, B and C both our options are right So I will I'll make it correct there Fine, moving to the next question Okay, still 31 Okay, 31 have written B Okay, I'll see Next one is do this one So So moving to the next question This is the question, please read it carefully Answer the Okay, fine There are four testu baby cd Half filled with water A considerable quantity of sugar, milk, egg white white and common salt was added in them, respectively With steering the contents of each tube, true solution will be contained in which solution in which of them Sugar, milk, egg white and common salt Okay So you tell me the true solution is present in which of them So last 5 seconds and let's see this time I think all of you will do this right Oh my god Still you people have made it wrong True solution will be with the salt and sugar Okay, so that will be the true solution But I want to explain you that question number 5, okay Because in next question you may need help from that question number 5 So please solve it now Last one tell me what is the answer Okay, how to do it that's an important part How to do is an important part Can you solve this question all of you Please solve it and tell me the answer The solubility of solute is 8 Okay, fine But solve it, solubility of solute is 8 Okay And you need to density is 1.364 Find the weight by volume percentage, can you do that weight by volume percentage Okay, I will tell you solubility of solute is 8 What do you mean by this 8 gram of solute It's on screen Sir has left audio Sir isn't there This connection is there Sir is there Sir left audio Two of the questions were wrong man Okay I know Chill You gotta try that side Okay, okay please Please don't make noise Okay see, so Sir we don't see your screen I am sharing one minute It got disconnected Yes, now you can see Just a minute I am sharing it again Can you talk a little louder Yes, yes Now can you see my screen Thank you Yes, can you see my screen now Okay Fine, so I was explaining this question If you see the solubility of the solute Please mute your mic If you see the solubility of solute What is that One minute If you see the solubility of solute That is this Okay one minute This one was the question Okay, so 8 gram of solute can be dissolved in 100 gram So just assume 100 gram of solute Just assume 100 gram of solute Okay is there 100 gram of solute is there This is our assumption Okay this is our assumption Okay now what you will say If 100 gram of solute is there So mass of solution is Mass of solution is 108 gram Density is given 1.36 Density is 1.36 Mass of solution you have Density you have Density is nothing but 1.364 Implies volume of solution is Volume is nothing but Mass divided by density 108 divided by 1.364 Here from here You will get the volume They asked you to find the weight by volume percent Percentage weight by volume All of you know that Mass of solute Mass of solute Divided by volume of solution Volume of solution This is the percentage weight by volume This is the concentration term Into 100 Mass of solute volume of solution Into 100 This is percentage weight by volume Volume of solution you can get from this equation Let's say this is x Mass of solute is 8 Percentage weight by volume is 8 by x into 100 You will be, you will going to get 10 I am saying that why I have explained this This equation will be helpful in solving one question Which will come afterwards So if you have any doubt please ask Any doubt No, this is the percentage weight by volume Mass of solute Divided by volume of solution Okay fine So moving to the next question Okay see Now we have the next question Please see the leader board first Then we will move to the next Through R&R line is leading As of now Okay fine So please see the question Question is the choose the correct Incorrect statement about truth solution Incorrect statement About truth solution Its component cannot be separated by Filtration Its particles can unstable Its particles cannot be seen by naked eye It does not show tinder effect Choose the incorrect statement Okay Very easy question But I think Truth solution Truth solution What all the filtration Or pack Okay fine So the answer for this is Answer for this is 39 students have done this right You know truth solution is Truth solution is You know its a transparent First of all So do you want me to discuss this question See Okay fine No, sure Okay I want to tell you Truth solution okay what was the answer then What was the answer which was wrong Truth solution does not show tinder effect Truth solution does not show Truth solution does not show tinder effect And solutions are seen by naked eye You can't see the solution by naked eye Even you can't see using microscope also For the truth solution Understood Any doubt Okay if anyone has any doubt please ask Okay fine moving to the next question First we will see the leader board Okay Prateep Tejaswi R&R 9 Still leading Oh good Fine moving to the next question Be ready for that Barium sulphate disperse in water Used in diagnostic x-ray is a Barium sulphate disperse in water Used Diagnostic x-ray is a Collide solution Suspension and foam Then you need to Use your brain in this question I'm telling you If you have not heard about this question It doesn't matter You have to use your brain and answer this question Most of you are thinking we have not heard about this So what to do But if you Think about barium sulphate You can easily answer this question Monisha you have But you have to accept this and Oh it's time sir And the answer is It is suspension Okay students I want to ask you one thing Is barium sulphate soluble in water or not Just tell me one thing Is barium sulphate soluble in water Is barium sulphate soluble in water No sir No idea students barium sulphate is not soluble in water If barium sulphate is not soluble You put into water It will settle down And it will form suspension Okay It depends on question to question You have to see the time Pratham Because this question is For this question I said 45 seconds For some Christians I have said 120 seconds and for some 90 seconds Okay so based on Question to question you are getting time Any doubt in this question Sir can you show Leader would I show you First tell me any doubt No doubts Okay fine Prathik is still living fastest also Very good Prathik Please read the question Care properly and then answer How many litres Of 15% mass by volume Sugar solution Would it take to get 75% of sugar How many litres of 15% Mass by volume sugar solution Would it take to get 75 gram of sugar A, B, C, D Corresponding to like One is equivalent to B, C, C, D How many litres No you don't know but you have to use That's why I told you in last question Somewhere you are going to use this This formula Percentage mass by volume What I said Use that percentage mass by volume For sugar solution And 75 grams of sugar you have Students will still have 30 seconds Okay the question is good That's why it took long Don't worry Nisha Okay how many litres of 15 gram Percentage mass by volume sugar solution 75 gram sugar Salute mass is given to you 75 gram Just you need to find the Okay 35 students have answered it right But I think There is a need of explaining this question I can't skip this question I think it's question number 10 Yes Just give me one second I will explain this then we will Move to the next question Okay See very easy question Just remember the percentage Weight by volume What is the percentage weight by volume I told you in my class also those who are Not in my class Percentage weight by weight is Weight of salute Okay I will do one thing So that you can Divide it by I will tell you why I am Changing colour also here Divide it by weight Of Solution Now you know Why I have written weight of salute This red thing will remain common No matter whatever the concentration Terms you want Like if you have percentage Weight by volume So what you are going to write Salute remain as it is here Weight of salute Divided by Volume of solution Because it is percentage weight by volume Volume of solution This is percentage weight by volume If you have percentage volume by volume What is the formula What is the formula percentage volume by volume Okay into 100 Don't forget to write into 100 Sorry my dear Into 100 Volume by volume Weight Volume of solution Volume of salute Divided by volume of solution Okay this is the common formula Which you can apply anywhere Into 100 Okay now Now see how to do this question Percentage given to you 15 So mass of salute is also given to you Mass of salute Divided by volume of solution Volume of solution You don't know So mass of salute is 15% Okay into 100 also you need to do What I can write 15 equals to 75 gram Divided by volume Into 100 What is the volume then Volume is Volume of solution you are going to get Why people made this wrong I have no idea Okay it is 0.5 litre 0.5 litre because The answer will be in ml Answer will be in ml you need to convert it Into litre Any doubt yes you are going to get 500 ml Okay fine any doubts Please put nn If you have no doubt Okay fine coming to the next Question First we will see the leader boon Why Pratik why you made mistake in this Question I have no idea The question was very easy and I explained many times in class I got it right Okay you have written I wrong I don't know why you have written Read the question carefully White gold is used in jewellery and contains two elements Gold and palladium Very less reactive Both are very less reactive That's why you get both them in jewellery A jewellery has two different samples So this is very honest Jewellery has two different samples That are both identical In appearance And have a uniform composition Throughout What can be said about the samples What can be said about the samples They are homogeneous mixture And can be classified as Metallic alloy Okay I think most of you are answered also 43 The material are homogeneous mixture And can be classified by their components The samples have Variable composition And reclassify as Metallic solution And D the samples are Heterogeneous mixture That can be separated using magnetic property Yes I am sharing the link of test Just after this class Just after this class Okay Answer for this question is Most of you have answered it right Very good students You can answer this question Very easy I think most of you got it right only But still Few of them have done it wrong For them Okay Okay There are two metals Two metals are given to you One is the gold and one is the palladium Okay a jewellery has two different samples Now Uniform composition What can be said about this They are homogeneous mixture Homogeneous mixture I told you And can be classified as Metallic alloys That is the correct answer Any doubt No Okay fine So coming to the next question See and the metallic is a Heterogeneous mixture it's not heterogeneous mixture Okay this I explained in class Though alloys are Alloys are homogeneous mixture Alloys are actually exception Alloys are a homogeneous mixture Yes I told you It is an exception Can you separate alloys Can you separate alloys Can you separate alloys Yes and fix this Can you separate alloys I will share the link for the test Don't worry Okay Fastest was the Prateek Coming to the next question Be ready for that Solubility is good separation technique For what Very very important question I want to explain one Small topic with help of discussion That's why I gave this Solubility is good separation technique For what thing Pure metals Noble gases Different salts metallic alloys Okay I am telling you Solubility Solubility is a good technique For what You have to think it's not like you will Okay fine And it's time sir Okay fine Most of you have given the right answer Now I want to tell you very important thing Very very important thing What is that important thing That solubility questions You know I want to give you an example Let's say One second See if there are two salts There are two salts You have the option to use the Solubility one is soluble Another is not How you decide which is soluble Okay one minute See okay This is the question I want to explain you one thing What is that Whenever you have a solubility related question You need to think like that Okay let's say you have two things Barium sulphate Barium sulphate And AGCL let's say Okay now What should I do What should I add so that I can Separate these salts How can I separate these salts Any idea Any idea both are precipitated How could I separate it Any idea So what I do That's what I want Crystallization okay fine But what I want to say These are both insoluble salts But if you want to separate them What you can do Let's say if I add calcium sulphate In that If I want to separate barium and aluminium What will happen Okay just give me one second And I'll give you one more example Let's say This is barium sulphate is insoluble AGCL is insoluble But you know calcium chloride is soluble Calcium chloride is soluble And calcium sulphate is insoluble Calcium sulphate is insoluble Okay these things you need to remember Calcium sulphate is insoluble And calcium chloride is soluble So what you do You add something Which can dissolve this AGCL Okay so what I want to tell Like if you put CACL to in this Your AGCL will get dissolved Okay let's say any calcium salt Any calcium salt like I am taking Calcium Which soluble salt can I take now Let's say Calcium salts of let's say Any salt which having a calcium plus 2 ion What will happen Calcium will form the Calcium plus 2 is there Yes now it will dissolve the AGCL Why Because calcium will react with Calcium minus to form a CACL2 CACL2 it will be soluble And but CA CA will not dissolve in sulphate In SO4 CA is not soluble That's why what you are going to get You are going to get a precipitate A very good example One more example is there Let's say you have an aluminium chloride You have aluminium chloride And there is one more thing That is zinc chloride If you have these two salts How to separate them You know what you need to do You put NaOH in both of them If you put NaOH both are soluble If this is a salt A This is salt B A and B are soluble A and B are soluble First level A and B ALCL3 and ZNCL3 ZNCL2 Both get dissolved Both get dissolved Both get dissolved What are the compounds from ALOH whole thrice And ZNOH whole thrice So now what we can write A and B both are insoluble Both are insoluble Now there is a very important point If you put NH4OH Ammonia One is soluble One is soluble means ZN is This will get dissolved Zinc hydroxide will get dissolved So Zinc hydroxide Zinc hydroxide get dissolved Get dissolved But No change in aluminium hydroxide If you put ammonia here No change So what I want to tell Whenever there are two salts You have an option to use Different type of solution Why it is getting dissolved Because these two salts are Amphoteric in nature Write the word Amphoteric Amphoteric in nature You may ask what all salts are Amphoteric in one class Just you can remember 10 Be You can It is remember like this So you can remember like this So these are all These are all Amphoteric metals Or these are all forming Amphoteric oxides Amphoteric oxides Always remember 10 pb, al, b, e, c, r, g, a, pb And there is Zinc, al and pb is important for you For you to learn There are many in 11th you will need this But zinc aluminium flood You need to remember it now It is very very important But I think you know that I am Doing good yes I made it Any doubt in that Any doubt in that question No sir Okay moving to the next question We are ready for that Okay So Pratik is still leading Good Pratik Very good Jagra I think Jagra In the last I think You want that, you got the first position If I remember it Correct You have prepared 4 different Mixer in water using charcoal powder Chalk powder, slagged lime And detergent powder Please read the picture carefully If you filter these mixers through a filter paper There will be no residue left After filtration in case of Chalk powder, chalk powder Slagged lime, detergent powder Very very important question I don't know Slagged lime Why do people don't know Okay for your help I can tell you Slagged lime means nothing But C.A.O.S. whole twice C.A.O.S. whole twice is slagged lime C.A.O.S. whole twice C.A.O.S. whole twice Which of them will pass Through the filter paper Okay you have 20 seconds left Which of them is going to pass Which of them is going to pass Chalk powder, chalk powder, slagged lime And detergent powder Last 7 seconds No residue left means Should pass through the filter paper And I think most of you Have done it wrong You know There is very important point Most of you think like that But you know there is a very important point That's why I have added this question Many of you have this misconception That slagged lime C.A.O.S. whole twice Is soluble in water That's why you have written It will pass through the filter paper But the fact is Calcium hydroxide is Insoluble Or slightly soluble in water Calcium hydroxide is Slightly soluble in water Slightly soluble in water Slightly soluble in water Slightly soluble in water That's why it will not pass You will get the precipitate there Okay, what all soluble Calcium sulphate Insoluble Calcium hydroxide All the hydroxide Other than the group 1 atom Group 1 metal Generally all hydroxides are insoluble What are the group 1 metal These These are the group 1 metal in the periodic table Other than these metals All hydroxides are insoluble Mostly And one more is that Ammonium hydroxide All these hydroxides are soluble Rest all are insoluble Okay, how to Remember this I have a history for this So remember it is in Hindi Halina ki rham se pariyar F.R. is the last atom But it is a radioactive Don't study that Halina ki rham se pariyar All these are group 1 atoms Okay this is a trick Halina ki rham se pariyar Halina ki rham se pariyar Okay These are all group 1 atoms Later in periodic table I will tell you more tricks Not now Moving to the next question First we will see the leader board Okay Okay fine Now see Pratik is still leading Fine and Vihan is the fastest Very good Vihan There is one more question for you And this is the last question So Nisar Okay look at your phone Okay wait wait wait Wait students wait students So what's the answer I will tell you the answer Wait wait So there is no question This thing is on the slide Okay fine I will show in the slide Wait wait you can answer yes I will show in the slide So what time is it Okay then Answer it D Answer it D D for dog So Saf has already answered Okay fine We will see the question then Okay see the question is this Sir can we repeat this question Okay see this is the question When light is passed through the sample When the light is passed through the sample A and B in a light room What the effect observed Are as shown in the figure Which one of the following pairs Is the correct description of both the samples Can you tell me what is that Here the light is passing You know light is passing But it is not Scattering What is the possibility of first If it is not scattering It does not scatter means Light is passing but does not scatter What does this mean Solution Okay now why Light is visible in a path of light See visible path of light is there So there are two possibilities What two possibilities It may be suspension It may be Suspension it may be Colloid Any of these are the possibilities Now they are given the option gel Gel is a colloid So this is not an answer Gel is a colloid Okay now A solution and B solution A and B both are solution No no this is also not correct Now A gel and B Suspension Is A gel and B suspension A is not gel Because gel is nothing but colloid Gel is nothing but colloid A solution B gel C gel See we can ignore but A solution and B gel That seems a correct answer A is the solution And gel is there means it is a colloid Understood Any doubt Please ask if anyone has any doubt Okay fine Okay fine Move it to the next I will see the I will show you the Result Okay fine So you could have wait for this So now answer for the leader goal Vihan, ITR, YTR 9 Who is leading in this Who is Agra The Agra was the fastest Oh Pratik Tejasvi R & R 9 Got this Pratik Congratulations Okay Jagra no problem You are second It's a very good fight and very good Jagra Both of you Pardon What you are saying Okay Jagra said he got in Say 20 seconds But I got in 4 here Okay fine So it's good congratulations students Okay and I think About the concentration terms That is a very important part Okay so Any doubt you have please ask Any doubt Okay if anyone has any doubt please ask Okay fine Thank you students Thank you all of you Thank you sir bye Thank you Thank you sir Thank you sir Okay thank you students Okay thank you Nishant I know that Okay but still it's It's for all For all it's same yes Okay I am sharing that link With you in INR 9 Thank you students