 to x is u times intv function which goes integration, differentiate it which is difficult which is easier to integrate. So, we choose you as that function which is difficult, difficult. Now, so according to all you can say what is xc inverse x, heavy or not so far. So, this function product I will do like this. Fixed in this one, I will do this point. So, do not think that I have two functions are involved. If you start up sometimes add functions whose integration we do not know so far which is log x function. So, this can work is you substitute sin inverse x as theta which is like sin inverse x is theta which implies x is sin theta which implies d x is cos theta d theta. So, when you do cos theta you get this expression. Now, do not think like oh the x cos x like that. Then theta becomes an algebraic one into integral which gives you answer as x. So, theta is what this approach as well. So, x square plus cos x cos square just add this as u. This should be v which is minus 1 by this. So, can I just make it plus of course, this will go off. So, when I split this term like these two terms I can see this is.