 Hello and welcome to the session. In this session we will discuss the following question and the question says, construct an equilateral triangle ABC such that the length of one of its sides is 6 centimeters. Let's start the solution now. Now we are given an equilateral triangle ABC. So we are given that triangle is equilateral and we know that the length of all the sides of an equilateral triangle is same since the length of one of its sides is 6 centimeters. Therefore, the length of all the sides is equal to 6 centimeters that is AB is equal to BC is equal to AC is equal to 6 centimeters for triangle ABC. So we have to construct a triangle ABC in which the length of all the three sides is equal to 6 centimeters. We shall write down the steps of construction now. Step one is draw a line segment BC which is equal to 6 centimeters. So we have drawn a line segment BC of length 6 centimeters. Step two is with BS center and radius 6 centimeters draw an arc. So with BS center and radius equal to 6 centimeters we draw this arc. Step three is with CS center and radius 6 centimeters draw another arc such that it intersects the previous arc. Let this point be A. So with CS center and radius equal to 6 centimeters we draw another arc and the point this intersection of these two arcs is the point A. Step four is join AB and AC. So we will now join the points A and B and A and C. So we have constructed the triangle ABC in which AB is equal to 6 centimeters BC is equal to 6 centimeters and AC is equal to 6 centimeters. Hence triangle ABC is the required triangle. With this we end our session. Hope you enjoyed the session.