 So to find the viscosity of the gas, we're going to be using equations 3.736. So those equations are mu g is going to equal to 1 times 10 to the negative 4 times k, which is a constant, e to the x, which is a constant times rho g to the y power. So that's all in the exponent right there. k is going to equal 9.379 plus 0.01607 times the molecular weight of the gas times t to the 1.5, all divided by 209.2 plus 19.26 times the molecular weight of the gas plus t. These temperatures will be in ranking, by the way. So that's important to note. All the t's in these equations will be for viscosity gas. x is going to equal 3.448 plus 986.4 over t plus 0.01009 times the molecular weight of the gas. And y is going to equal 2.447 minus 0.2224 times x. So the first thing we can solve, we can solve for k. Your x first, I'll solve for x first. It's going to be 3.448 plus 986.4 divided by your temperature in ranking, which will be 580 plus 0.01 zero zero nine times the molecular weight of gas, which we saw earlier, which is 20.279. And that's pound per pound mole. So this is going to equal 5.353. So this one next is going to equal 9.379 plus 0.01607 times 20.279 all times 580 to the 1.5 power divided by. So k is going to equal 114.9. And then y will just equal just by plugging in x that we already found. That's 2.447. Y is going to equal 1.25649. Plugging these in. Density of gas for, this is at 2,000 psi by the way. I forgot to write it down, but that's what it was that we found earlier. So then we can find our viscosity of our gas, which is going to equal. Our gas viscosity should be 0.01298. It's important to note in this equation, which I may have said incorrect earlier, this rho g needs to be in terms of gram per centimeter. And it can't be in terms of pound per foot cubed. Or you're going to have very high values for viscosity. So to convert from grams, to convert from a pound per foot cubed to grams per cc, it's in the notes. So the equation we'll be using is going to be rho g in terms of gram per cc. It's going to equal 1.4935 times 10 to the negative third times your molecular weight of your gas, which is going to be 20.279 times your pressure, which is going to be 2,000 psi. And then this is all going to be divided by z, which was 0.825, I believe. And then times your temperature, which temperature will have to be in ranking, which is going to be 580. And so this will give us a rho of gas, which is equal to 0.12659 grams per cc, which this will be plugged into up here. So having those constants as it is, you should get this. I'll just make sure you get something close. I got 0.012617, which is pretty close to that. So that's how you find viscosity of a gas, blow bubble point. In terms of what's really important in this problem, it's not necessarily the equation itself. It's more about the concepts and seeing the trends. So for example, your gas oil ratio, like if I were to draw in terms of a graph, this would be your pressure. This would be your gas oil ratio. So as your pressure increases, your gas oil ratio is going to increase as well up until you reach bubble point, and then it's going to be constant. So this would be your bubble point pressure, for example. And like I said earlier, because you can't dissolve any more gas into your reservoir oil, and so you're not going to have a higher GOR, your gas oil ratio. So that's important to note. So that's why you don't have to worry about GORs above bubble point. And like seeing with BO, like I said earlier, your BO is going to, at first, it's going to increase. And then once you reach bubble point, it's going to fall back down, just because you're not going to be able to dissolve any more gas. So it's going to be able to be compressed more. Not necessarily compressed more, but you're not going to take up gas volume. So that's why it's going to be able to be compressed. So this would be pressure, and this would be BO. And so noting that your formation volume factor of oil is always going to be highest at your bubble point pressure, it's always going to be the lowest at your lowest pressure, which at standard conditions, it will be one, because it's what a stock tank, or you say your stock tank conditions to, it would be one. And like with a Z factor, make sure you're using the right units. For these equations, all these equations, you need to make sure you're using the right temperature. And just like with this viscosity of gas, you need to make sure you're using the right density. So knowing which equations and which units to use for them are very important. And so like as we said, also, like with gas, we don't really care about the properties of bubble bubble point, just because there really is no free gas in the reservoir at that point. And so we just can ignore calculating any values, because it wouldn't give us values that made sense anyway. So that's pretty much what the most important stuff is from the first problem.