 Hello and welcome to the session. My name is Mansi and I am going to help you with the following question. The question says, find an anti-derivative or integral of the following by the method of inspection AX plus B the whole square. So let us start with the solution to this question. First of all we consider D by DX of AX plus B the whole square. Now this is AX plus B the whole cube. So we consider D by DX of AX plus B the whole cube that is equal to 3 into A into AX plus B the whole square because we know that D by DX of X raise to power n is equal to n into X raise to power n minus 1. Now if we consider this to be X then we will have 3 into AX plus B raise to power 2 multiplied by derivative of AX plus B that is simply A. Therefore AX plus B the whole square will be equal to 1 by 3A into D by DX of AX plus B the whole cube. This implies that AX plus B the whole square is equal to D by DX of 1 by 3A into AX plus B the whole cube. Hence an anti-derivative of AX plus B the whole square is 1 by 3A AX plus B the whole cube. So this is our answer to the question. I hope that you understood the question and enjoyed the session. Have a good day.