 Hello and welcome to the session. Let us discuss the following question. It says integrate the following function. The given function is e to the power 2x plus 3. Let us now proceed on with the solution and let i be the integral e to the power 2x plus 3 dx. Now what is equal to 2x plus 3? So dt by dx is equal to 2 and this implies dt is equal to 2dx and this implies dx is equal to dt by 2. Now dx is equal to dt by 2 and t is equal to 2x plus 3. So the integral becomes e to the power t dt by 2 which is again equal to 1 by 2 into integral of e to the power t dt and we know that the integral of e to the power t is e to the power t. So this is equal to 1 by 2 e to the power t plus c where c is the constant of integration. Now put the value of t substitute t as 2x plus 3. It becomes 1 by 2 e to the power 2x plus 3 plus c. Hence the integral of the given function is 1 by 2 into e to the power 2x plus 3 plus c. So that is all for this session. Bye for now. Take care.