 Hi and welcome to the session. Let us discuss the following question. The question says in each of the following exercises 1 to 6 find the coordinates of the focus, axis of the parabola, the equation of the directorates and the length of the latest vector. Given equation of parabola s y square equals to 10x. Let's now begin the equation. Given equation is y square equals to 10x. We know that if the equation has a y square term then the axis of symmetry is along the x axis and if the equation is x square term then the axis of symmetry is along the y axis. Now here the given equation involves y square axis of symmetry is the x axis. We also know that if the coefficient of x is positive then parabola opens to the right. Now here the coefficient of x is positive so the parabola opens to the right. Now the equation y square equals to 10x can be written as y square is equal to 4 into 5 pi 2 into x. Now clearly this equation is of the form y square equals to 4ax. So on comparing y square equals to 4 into 5 pi 2 into x with y square equals to 4ax. We find that a is equal to 5 pi 2. We have learned that if the equation of the parabola is of the form y square equals to 4ax then its focus is at the point a0 and its direct trigger is x equals to minus a. So this means the focus of this parabola 0 equation of direct trigger x equals to minus 5 pi 2. Now we will find length of latest rectum. We know that length of latest rectum is equal to 4a. On substituting value of a we get 4 into 5 pi 2 and this is equal to 10. So length of latest rectum of the given parabola is 10. So focus of the given parabola is at the point 5 pi 2 0. This of symmetry is x axis. Direct trigger is x equals to minus 5 pi 2. Length of the latest rectum is 10. This is our required answer. So this completes the session. Bye and take care.