 Hi and welcome to the session, I am Shashi and I am going to help you with the following question. Question is, find the second order derivatives of the functions. The given function is sin log x. Now, let us start the solution. Let y is equal to sin log x. Here, we will apply chain rule to differentiate the function. So, we can write differentiating both sides with respect to x. d y by d x is equal to cos log x multiplied by 1 upon x. Or we can write d y upon d x is equal to cos log x upon x. Now, again differentiating both sides with respect to x, we get d square by upon d x square is equal to x multiplied by derivative of cos log x minus cos log x multiplied by derivative of x upon x square which is further equal to x multiplied by derivative of cos log x is equal to minus sin log x multiplied by 1 upon x square minus cos log x multiplied by 1 upon x square. Now, x n x will get cancelled and we get minus sin log x minus cos log x upon x square. So, the required second derivative of y is equal to minus sin log x plus cos log x x square. So, the required second order derivative is given by minus sin log x plus cos log x upon x square. This is our required answer. This completes the solution. Hope you understood the solution. Take care and goodbye.