 Hi and welcome to the session. Let's work out the following question. The question says draw a circle of radius 3.5 centimetre from a point P outside the circle at a distance of 6 centimetre from the centre of circle draw two tangents to the circle. So let's start with the solution to this question. We see the steps of construction for this one. One is draw a circle radius 3.5 centimetre. So like this we draw a circle of radius 3.5 centimetre. Step two is from centre O of the circle take a point P at a distance of 6 centimetre that this O P should be equal to 6 centimetre. So this is O P that is equal to 6 centimetre. Step three is draw a perpendicular bisector of O P which meets O P at M or which meets O P at M. So like this we draw the perpendicular bisector of O P that meets O P at the point M. Step four is taking O M as radius draw a circle which cuts the previous circle at the point S and T. So with the O M as radius we draw a circle which cuts the previous circle at the point S and the point T. Step five is join P S and P T. So this is how we join P S and P T. So P S and P T are required tangents from a point P outside the circle at a distance of 6 centimetre from the centre of the circle. So this is our solution to this question. I hope that you understood it and enjoyed this session. Have a good day.