 Hello friends and how are you all doing today? The question says an insurance company insured 2,000 scooter drivers 4,000 car drivers and 6,000 truck drivers. The probability of a scooter car at a truck meeting an accident are 0.01, 0.13 and 0.15 respectively. Here if one of the insured person needs with an accident we need to find the probability that he is a scooter driver. So after reading this question we can see that this is a question relating to base theory So let us proceed with the solution for that Here let E1 3 be the events of selecting scooter a driver respectively be the event of meeting right now have probability of E1 that is a scooter driver is given to us as 2000 probability of E2 that is car drivers are given to us as 4,000 and probability of E3 that is a truck driver given to us as 6,000. Further probability that an accident sorry scooter driver meets with an accident is 0.01 that is 1 upon 100 probability of E upon E2 is equal to 3 upon 100 and probability of E upon E3 is 15 upon 100 right we need to find out probability of that a scooter driver meets with an accident right so we have probability of E1 upon A equal to probability of E1 into probability of A in upon E 1 divided by probability of E1 into probability of A upon E1 plus probability of E2 into probability of A upon E2 plus probability of E3 into probability of A upon E3 3 now on substituting the values we have 2000 into 1 upon 100 divided by 2000 into 1 upon 100 plus 4,000 into 3 upon 100 plus 6,000 into 15 upon 100 on simplifying it we have 20 upon 1 divided by 20 plus 1 20 plus 900 which further gives us 20 upon 20 plus 1 20 140 so we have 1 0 4 0 over here on simplifying it further We have the answer as 1 upon 52 so 1 upon 52 is The probability that the person meeting with an accident is a scooter driver Right, so this completes the session. Hope you understood it well. I enjoyed it too. Have a nice day ahead