 Welcome to the session and let us discuss the following problem today. Is the following pair of linear equations consistent or inconsistent? If consistent obtain the solution graphically we have x-y is equal to 8 and 3x-3y is equal to 16. So let us write the solution now. Given to us the linear equations are x-y is equal to 8 and 3x-3y is equal to 16. The given system of equations 2 to 0 and 3x-3y-16 is equal to 0. Equations 2 to 0, a2x plus b equal to 0, we get 2 to 1, b1 is equal to minus 1, c1 is equal to minus 8 and a2 is equal to 3, b2 is equal to minus 3 and c2 is equal to minus 16. Now a1 by a2 is equal to 1 by 3 and b1 by b2 is equal to minus 1 by minus 3 which is equal to 1 by 3 and c1 by c2 is equal to minus 8 by minus 16 which is equal to 1 by 2. Therefore, we can see that a1 by a2 is equal to b1 by b2 is not equal to c1 by c2. Therefore, given pair of linear equations consistent, we understood the problem by an eye's day.