 So room temperature, it says, is 25 degrees Celsius. And the kinetic energy average is going to be 3 halves kT. So T, like we said, is 25 degrees Celsius. We've got to put it in Kelvin, so 273, so 298 Kelvin. And k is equal to R over NA. So R, remember, is 8.314 joules per mole Kelvin. This is given to you here. This will be given to you. NA is Avogadro's number, so 6.022 times 10 to the 23rd. OK, so let's solve for average kinetic energy. So 3 halves, I don't want to think about it that way. So times R, so 8.314 joules per 1 mole Kelvin times 1 over NA. So in that case, 1 mole is 6.022 times 10 to the 23rd. And if you want to think about it as molecules of hydrogen, you can. So moles of hydrogen, H2 molecules. So this mole is canceling out like that mole's there. And then times T, 298. So Kelvin is going to cancel with that Kelvin next. OK, so now we solve for energy average. So divided by 2 divided by 1, 6. And I got this number here, 6.17 times 10 to the negative 21 joules per molecule. So notice, this didn't have anything to do with, in particular, hydrogen. So what you'll find is the average kinetic energy of any gas at 25 degrees Celsius is this amount of energy. Doesn't matter what the gas is.