 Hi and welcome to the session. I am Tanika and I am going to help you to solve the following question. The question says evaluate the following limits and exercises 1 to 22 will limit our 4x plus 3 by x minus 2 as x tends to 4. Before solving this question we should know that if fx is a rational function that means fx is of the form gx by hx. Where gx hx polynomials such that hx is not equal to 0 then limit of fx as x tends to a is equal to limit of gx by hx as x tends to a. Other algebra of limits, limit of quotient of two functions is the quotient of the limits of the functions. That means limit of gx by hx as x tends to a is equal to limit of gx as x tends to a upon limit of hx as x tends to a. Now here gx and hx are polynomials and we have learned that limit of a polynomial function is the value of the function with the point to which x is approaching. So here x is approaching to a so this means limit of gx as x tends to a is g of a and limit of hx as x tends to a is h of a. The knowledge of this is the key idea in this question. Now begin with the solution. In this question we have to evaluate limit of 4x plus 3 by x minus 2 as x tends to 4. This function is of the form gx by hx and we know that limit of gx by hx as x tends to a is g of a by h of a. So this means limit of 4x plus 3 by x minus 2 as x tends to 4 is 4 into 4 plus 3 by 4 minus 2. This is equal to 19 by 2. Hence the required limit is 19 by 2. This is our required answer. So this completes the session. Bye and take care.