 That's true. OK, anyway, so let's try this problem and it says, what is the molality of a solution prepared but dissolving 32.0 grams of calcium chloride and 271 grams of water? So well, with molality, right, molality is going to be the number of moles of solute divided by the mass of the solvent in kilograms, right? I guess you remember that, in kilograms. So which one of these is the solvent of water, right? Is that in kilograms? No, so we're going to have to convert that to kilograms, right? If you guys remember how to do that? So grams over, or kilograms over grams, so if we did that, it would be 0.271 kilograms of water. Is everybody OK with that? Do I need to write it all out? So what do I have to do here? This is grams of calcium chloride, right? Is that the same thing as number of moles? So this is the solute. Is that right? Yes, OK. So what do I do to convert grams to moles? Yeah, or multiply by the inverted molar mass, right? So does anybody got a molar mass yet? Yeah, I think that's what I got. I got 9-8, but I'll just do 9-8, just so my numbers stay the same. OK, so grams of calcium chloride are 1 mole. So like that, OK? Cancel, cancel. Get your calculator out. 32 divided by 1, 1, 0. So what would be, how many sig figs is this thing going to have? 2, 3, very good, moles of calcium chloride divided. And then, yeah, so we got the two numbers we want, right? So we're just going to plug each other in. So 0.288 moles divided by 0.271 kilograms. And I get 1.06, and we say molal, molal, OK? And if you want to, you can say molal, calcium chloride. Is everybody OK on doing something like that? Any questions on something like that? Wonderful.