 Hello and welcome to the session. Let us discuss the following question. Question says, it is given that in a group of three students the probability of two students not having the same birthday is 0.992. What is the probability that the two students have the same birthday? First of all let us understand that for any event e probability of e plus probability of not e is equal to 1. Here e bar represents not e also e and e bar are called complementary events. Or we can say e and not e are complementary events. Now we will use this discussion as our key idea to solve the given question. Let us now start with the solution. Now we are given that the probability of two students not having the same birthday is 0.992. Now we have to find the probability of the two students having the same birthday. Now clearly we can see these two are complementary events and sum of probabilities of two complementary events is equal to 1. From key idea we know probability of e is equal to 1 minus probability of not e. Now let us assume that this event is represented by e and this event is represented by e bar. Now probability of not e is equal to 0.992. So we get probability of e is equal to 1 minus 0.992 which is further equal to 0.008. We know e represents this event. So we get probability of two students having same birthday is equal to 0.008. So this is our required answer. This completes the session. Hope you understood the solution. Take care and have a nice day.