 Hello and welcome to the session. In this session we will discuss a question which says that use the given graph to perform large reflection of 8 units to the right. Then a reflection over x axis while coordinates of the final image. Now before starting the solution of this question, we should know our result. And that is blind reflection. Now a blind reflection is the composition of the plane that consists of a line of reflection and a translation in the direction of the line of reflection performed in either order. Now this result will work out as a key idea for solving out the given question. Now let us start with the solution of the given question. Now whenever we are given a quadrilateral, let us label its vertices as A, B, C and D. Now we want to perform light reflection of 8 units to the right. Then a reflection over x axis. It means firstly we have exacerbated the figure 8 units to the right. Further by its reflection over x axis, so first we translate the given image. That is the quadrilateral A, B, C, D 8 units to the right. So we will not move up or down. Now here you can see that the scale on both the x axis and y axis is of 2 units. Thus each square is equal to 2 units. So from vertex A we have to move 8 units to the right. That is we count here there is 1, 2, 3 and 4 squares to the right because 2 into 4 is equal to 8 units. And when we place a point there and we label this similarly for each vertex we will count 4 squares to the right in order to move 8 units from the given point. So from vertex B we count 4 to the right. We place a point there and label it as B dash. Now again 4 squares to the right from vertex C we put a point there and this is the point C dash. And lastly from vertex D we count 4 squares we put a dot there and we label this point as D dash. Then we join image points to B dash, B dash to C dash, C dash to D dash and D dash to A dash. So we have the image coordinate A dash, B dash, C dash, D dash. And now we have to reflect this image coordinate A with x-axis, x-axis is the line. So the previous image and the image points are distant from x-axis. Now here you can see that the point 1, 2, 3 and 4 squares that is 8 units from the x-axis So we take its image point 3 and 4 squares while the x-axis on the opposite side of the dash lie on the same line. B dash is at a distance of 1, 2 and 3 squares that is 6 units from the x-axis. We take its image point B double dash also at a distance of 1, 2 and 3 squares from the x-axis on the opposite side. B dash and B double dash lie on the same line. We plot image points C double dash and D double dash and now we join the points A double dash to B double dash, B double dash to C double dash, C double dash to D double dash and D double dash to A double dash at the required image that is the coordinate A double dash, B double dash, C double dash, D double dash. Now let us write its coordinates, that is the coordinates of its vertices. Now the point A w dash has coordinates 2 minus 8. Point B w dash has coordinates 6 minus 6. Point C w dash has coordinates 4 minus 2. And point D w dash has coordinates 0 minus 4. So this is the solution of the given question. And that's all for this session. Hope you all have enjoyed the session.