 Hello and welcome to the session. The question says, in each of the exercises 1 to 9, find the coordinates of the pokai, the vertices, the length of the major axis, the minor axis, the eccentricity and the length of latest rectum of the ellipse. Both one is, x square upon 25 plus y square upon 100 is equal to 1. Now, an ellipse is the set of all the points in the plane, the sum of whose distances from two fixed point in the plane is constant. So, to solve this problem, please refer to version number 2 of this exercise in which you have given a detailed explanation of the pokai vertices and the length of major axis and minor axis, the eccentricity and the latest rectum. Now, here the given equation of ellipse is x square upon 25 plus y square upon 100 is equal to 1 or it can further be written as x square upon 5 square plus y square upon 10 square is equal to 1. Now, here the denominator of y square upon 100 is greater than the denominator of x square upon 25. Thus, the major axis along the y axis, the standard equation of the ellipse whose major axis is along the y axis is given by x square upon p square plus y square upon a square is equal to 1. Now, on comparing this, the standard equation with the given equation of the ellipse, we find here that a is equal to 10 and b is equal to 5. Thus, c which is given by a square minus b square is equal to root over 100 minus 25 which is equal to root over 75 and the focus f 1 and f 2 are given by 0 plus minus c and here c is root over 75. So, we have 0 comma plus minus root over 75 and the vertices are given by 0 comma plus minus a and here a is 10. So, we have 0 comma plus minus 10. Then we have the length of major axis that is given by 2 times of a. So, we have 2 into 10 that is equal to 20 and length of the minor axis which is given by 2 times of b that is 2 into 5 is equal to 10 and the eccentricity which is denoted by e is given by c upon a. So, c is root over 75 upon 10 and this can be written as 5 root 3 upon 5 into 2 cancelling the common factor we have root 3 upon 2. So, this is the eccentricity and the length of the major axis. So, we have 2 into b square is 25 upon 10 5 2 is a 10 5 5 is a 25. So, we have 10 upon 2 and 2 5 is a 10. So, this is further equal to 5. Hence, the answer is the 2 focus of the given equation of the ellipse is 0 plus minus root over 75 its vertices are given by 0 comma plus minus 10 length of the major axis is equal to 20. The length of the minor axis is equal to 10 its eccentricity just denoted by small e is equal to root over 3 upon 2 and the latest rectum 5. So, this completes the session. Hope you have understood it and please refer to version number 2 of this exercise. Take care and have a good day.