 So let's try and graph the circle with the equation x plus 2 squared plus y minus 3 squared equals 9. So the first thing to remember is that the circle with center h, k, and radius r has the equation x minus h squared plus y minus k squared equals r squared. So we need to rewrite the equation in standard form. So first we want to y minus k squared, and we already have it. We want our constant to be something squared, so 9 is 3 squared. And we also want an x minus h squared. And so remember that a minus negative b is the same as a plus b. And so we can rewrite this x plus 2 as x minus negative 2. And since our equation is now in the standard form, we can read off the location of the center and the radius. The center is at negative 2, 3, and the radius is 3. So we want to plot the center and then a point on the circle. So we'll go to the center negative 2, 3, plot our point, and expand out by 3 units to give us a circle of radius 3. Oh wait, we plotted the center at the wrong place. This is actually at negative 2, 4. So we need to reset clear all. This time we'll have to be a little bit more careful. We'll go to the center negative 2, 3, check that that's really the right point, click on the point, then move out 1, 2, 3 spaces to get the circle. And once we're satisfied that this is the circle with center negative 2, 3 with radius 3, we can click on the graph to mark the point and then submit our answer.